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# Jewels and Stones

Given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".

Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:

Input: J = "z", S = "ZZ"
Output: 0


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Solution submitted by Dzeng at March 28, 2020, 11:23 p.m.
j = 'abc' s = 'aaAAbBBB' jcount = 0 for i in j: jcount += s.count(i) print(jcount) 

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